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Find the equation of the straight line passing through A(10,-2) and B(4,1)

Sagot :

Answer:

y = - [tex]\frac{1}{2}[/tex] x + 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = A(10, - 2) and (x₂, y₂ ) = B(4, 1)

m = [tex]\frac{1+2}{4-10}[/tex] = [tex]\frac{3}{-6}[/tex] = - [tex]\frac{1}{2}[/tex] , then

y = - [tex]\frac{1}{2}[/tex] x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (4, 1 )

1 = - 2 + c ⇒ c = 1 + 2 = 3

y = - [tex]\frac{1}{2}[/tex] x + 3 ← equation of line

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