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If we add 22.5 g of HCl to 45.8 g of water, what is the percent by mass of HCl in the solution?

Sagot :

sebassandin

Answer:

[tex]\%m/m=33.0\%[/tex]

Explanation:

Hello there!

In this case, since the percent by mass of a solute in a solution is computed via the following division:

[tex]\%m/m=\frac{m_{solute}}{m_{solute}+m_{solvent}} *100\%[/tex]

Next, given the mass of HCl and that of water, we plug them in to obtain:

[tex]\%m/m=\frac{22.5g}{22.5g+45.8g} *100\%\\\\\%m/m=33.0\%[/tex]

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