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Sagot :
Answer: The formula of the hydrate is [tex]MnSO_4.2H_2O[/tex]
Explanation:
Decomposition of hydrated manganese sulphate is given by:
[tex]MnSO_4.xH_2O\rightarrow MnSO_4+xH_2O[/tex]
Molar mass of [tex]MnSO_4[/tex] = 151.0 g/mol
According to stoichiometry:
(151.0+18x) g of [tex]MnSO_4.xH_2O[/tex] decomposes to give 151.0 g of [tex]MnSO_4[/tex]
Thus 45.91 g of [tex]MnSO_4.xH_2O[/tex] decomposes to give= [tex]\frac{ 151.0}{151.0+18x}\times 45.91g[/tex] of [tex]MnSO_4[/tex]
Also we are given : 37.07 g of [tex]MnSO_4[/tex] is produced
Thus we can equate the two equations:
[tex]\frac{ 151.0}{151.0+18x}\times 45.91=37.07[/tex]
[tex]x=2[/tex]
Thus the formula of the hydrate is [tex]MnSO_4.2H_2O[/tex]
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