Answer:
y=[tex]\frac{-3x}{2}[/tex]
Step-by-step explanation:
Hi there!
We need to find the equation of the line that passes through the origin (the point (0,0)) and (-2,3)
There are 3 ways to write the equation of the line, although the most common way is slope-intercept form.
Slope-intercept form is given as y=mx+b, where m is the slope and b is the y intercept
So we need to find the slope of the line first
The formula for the slope (m) calculated from two points [tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex] where ([tex]x_{1}[/tex],[tex]y_{1}[/tex]) and ([tex]x_{2}[/tex], [tex]y_{2}[/tex]) are points
We have the needed information to calculate the slope, but let's label the values of the points to avoid any confusion
[tex]x_{1}[/tex]=0
[tex]y_{1}[/tex]=0
[tex]x_{2}[/tex]=-2
[tex]y_{2}[/tex]=3
Now substitute their values into the equation and find m
m=[tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]
m=[tex]\frac{3-0}{-2-0}[/tex]
subtract
m=[tex]\frac{3}{-2}[/tex]
so the slope of the line is [tex]\frac{3}{-2}[/tex]. It can also be rewritten as [tex]\frac{-3}{2}[/tex]
Here is the equation of the line so far:
y=[tex]\frac{-3x}{2}[/tex]+b
we need to find b
As the equation passes through both (0,0) and (-2,3), we can use either one of them to solve for b
Let's take (0,0) for this case
Substitute 0 as x and 0 as y
0=-[tex]\frac{3}{2}[/tex](0)+b
multiply
0=0+b
add 0 to both sides
0=b
So b is 0
The equation of the line therefore is y=[tex]\frac{-3x}{2}[/tex]
Hope this helps!
