Answered

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for the following equilibrium, where mgf2 is the only species in liquid water, if the magnesium concentration is 0.0025 m and ksp=8.7×10−14, will a precipitate form? mgf2(s)↽−−⇀mg2 (aq) 2f−(aq)

Sagot :

okpalawalter8

We have that Precipitate will be form because

ksp>Ionic Product

[tex]8.7 x 10^{-14} > 6.25 * 10^{-8}[/tex]

From the question we are told

for the following equilibrium, where mgf_2 is the only species in liquid water, if the magnesium concentration is 0.0025 m and ksp=8.7×10−14, will a precipitate form?

mgf2(s)↽−−⇀mg^2 (aq) 2f−(aq)

Generally

With Solubility as mol^{-1}

[tex]s=0.0025\\\\2s=0.005[/tex]

Since from the equation RHS

[tex]mg^2 (aq) 2f−(aq)[/tex]

Therefore

Ionic Product

[tex]X=Mg^{+2} *F^-^2\\\\X=s*2s^2\\\\X=4s^3\\\\X=4*(0.0025)^3\\\\X=6.25 * 10^{-8}\\\\[/tex]

Hence

Precipitate will be form because

ksp>Ionic Product

ksp>x

8.7 x 10^{-14} > 6.25 * 10^{-8}

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