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a marble rolls horizontally off a table that is 0.8m tall. if the marble lands 0.6m from the base of the table, what is the initial velocity of the marble?

Sagot :

onyebuchinnaji

The initial velocity of the marble from the given position is  1.49 m/s.

The given parameters;

  • height of the table, h = 0.8 m
  • horizontal distance traveled by the train, X = 0.6 m

The time of motion of the marble from the given height is calculated as;

[tex]h = v_yt + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 0.8}{9.8} }\\\\t = 0.404 \ s[/tex]

The initial horizontal velocity of the marble is calculated as follows;

[tex]X = v_0_xt\\\\v_0_x = \frac{X}{t} \\\\v_0_x = \frac{0.6}{0.404} \\\\v_0_x = 1.49 \ m/s[/tex]

Thus, the initial velocity of the marble from the given position is  1.49 m/s.

Learn more here:https://brainly.com/question/21180604

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