Answered

At Westonci.ca, we connect you with experts who provide detailed answers to your most pressing questions. Start exploring now! Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

Can someone please help?

Can Someone Please Help class=

Sagot :

sqdancefan

Answer:

  (a) no

  (b) -1, (2, -1)

  (c) 4, (4, 7)

  (d) no

Step-by-step explanation:

(a)

You can check by using x=3 in the function.

  f(3) = 4(3) -9 = 12 -9 = 3 . . . . not -3

The point (3, -3) is not on the graph.

__

(b)

Put x=2 into the function and evaluate:

  f(2) = 4(2) -9 = 8 -9

  f(2) = -1

  The point (2, -1) is on the graph.

__

(c)

Put f(x) = 7 into the equation and solve for x.

  7 = 4x -9

  16 = 4x

  4 = x

  The point (4, 7) is on the graph.

__

(d)

  no, see part (b)

View image sqdancefan

  • f(x)=4x-9

#a

  • (3,-3)

Lets check

[tex]\\ \rm\rightarrowtail -3=4(3)-9=12-9=3[/tex]

  • No

#b

x=2

[tex]\\ \rm\rightarrowtail f(2)=4(2)-9=8-9=-1[/tex]

#c

  • f(x)=7

[tex]\\ \rm\rightarrowtail 4x-9=7[/tex]

[tex]\\ \rm\rightarrowtail 4x=16[/tex]

[tex]\\ \rm\rightarrowtail x=4[/tex]

#d

  • x=2

Already done in 2nd bit .

  • No not a zero
We appreciate your time. Please come back anytime for the latest information and answers to your questions. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.