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Sagot :
Answer:
(a) no
(b) -1, (2, -1)
(c) 4, (4, 7)
(d) no
Step-by-step explanation:
(a)
You can check by using x=3 in the function.
f(3) = 4(3) -9 = 12 -9 = 3 . . . . not -3
The point (3, -3) is not on the graph.
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(b)
Put x=2 into the function and evaluate:
f(2) = 4(2) -9 = 8 -9
f(2) = -1
The point (2, -1) is on the graph.
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(c)
Put f(x) = 7 into the equation and solve for x.
7 = 4x -9
16 = 4x
4 = x
The point (4, 7) is on the graph.
__
(d)
no, see part (b)
- f(x)=4x-9
#a
- (3,-3)
Lets check
[tex]\\ \rm\rightarrowtail -3=4(3)-9=12-9=3[/tex]
- No
#b
x=2
[tex]\\ \rm\rightarrowtail f(2)=4(2)-9=8-9=-1[/tex]
#c
- f(x)=7
[tex]\\ \rm\rightarrowtail 4x-9=7[/tex]
[tex]\\ \rm\rightarrowtail 4x=16[/tex]
[tex]\\ \rm\rightarrowtail x=4[/tex]
#d
- x=2
Already done in 2nd bit .
- No not a zero
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