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f(x)=x²-12x + 3 find vertex

Sagot :

The function f(x)=x²-12x + 3 is a quadratic function, the vertex is given as x = -b/2a

f(x)=x²-12x + 3

a = 1, b=-12, c=3

x = -(-12)/2(1)

x = 12/2

x = 6

to get the y-coordinate, substitute x = 6 into f(x)

f(6) = 6²-12(6) + 3

= 36-72+3

=-33

the coordinate of the vertex is (6, -33)