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Sagot :
Equation of a line in slope intercept form:
[tex]y=mx+b[/tex]m is the slope
b is the y-intercept
To find the slope use the two given points in the next formula:
[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ \\ \text{points: }(-4,-2)(3,7) \\ \\ m=\frac{7-(-2)}{3-(-4)} \\ \\ m=\frac{7+2}{3+4}=\frac{9}{7} \end{gathered}[/tex]Use the slope and one of the points to find the y-intercept:
[tex]\begin{gathered} y=mx+b \\ (3,7) \\ \\ 7=\frac{9}{7}(3)+b \\ \\ 7=\frac{27}{7}+b \\ \\ 7-\frac{27}{7}=b \\ \\ b=\frac{49-27}{7} \\ \\ b=\frac{22}{7} \end{gathered}[/tex]Then, the equation of the line passing through the given pair of points is:
[tex]y=\frac{9}{7}x+\frac{22}{7}[/tex]
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