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Sagot :
We will have the following:
Part A:
The x-intercepts represent the prices of the goods than wen sold represent no net gain or loss.
The maximum value represents the price at which there will be a maximum profit.
Part B:
We will have that the increasing and decreasing intervals are respectively:
[tex]I_{\text{increaing}}=(-\, \infty,3)[/tex][tex]I_{\text{decreasing}}=(3,\infty)[/tex]They tells us respectively that:
Increasing: The greater the price the greater the profit.
Decreasing: The greater the price the smaller the profit.
Part C:
We determine the equation of the parabola. We can see that it's vertex is located at (3, 120), we can also see that the parabola passes by the origin (0, 0); so:
[tex]f(x)=a(x-3)^2+120\Rightarrow0=a(0-3)^2+120[/tex][tex]\Rightarrow0=9a+120\Rightarrow9a=-120\Rightarrow a=-\frac{40}{3}[/tex]So, the equation that represents the parabola is:
[tex]f(x)=-\frac{40}{3}(x-3)^2+120[/tex]Then, we will determine the average rate of change as follows:
[tex]\text{average rate of change}=\frac{f(b)-f(a)}{b-a}[/tex]So:
[tex]\text{average rate of change}=\frac{(-40/3((3)-3)^2+120)-(-40/3((1)-3)^2+120)}{3-1}[/tex][tex]\text{average rate of change}=\frac{80}{3}\Rightarrow average\text{ rate of change}\approx26.67[/tex]So, the avereage rate of change for the graph from x = 1 to x = 3 is exactly 80/3, that is approximately 26.67.
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