Answered

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If h(x) = 3(x2 + 1) - 6, what is the value of h(10)?

Sagot :

[tex]\begin{gathered} h(x)=3(x^2^{}+1)-6 \\ \text{when they ask by h(10) you must substitute 10 in the place of x:} \\ h(10)=3(10^2+1)-6 \\ h(10)=3(100+1)-6 \\ h(10)=3(101)-6 \\ h(10)=303-6 \\ h(10)=297 \end{gathered}[/tex]

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