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Sagot :
In a number cube, the sample space is {1,2,3,4,5,6}.
The even numbers are {2,4,6}.
Determine the probability for cube landing with even number first times.
[tex]\begin{gathered} P(A)=\frac{3}{6} \\ =\frac{1}{2} \end{gathered}[/tex]Determine the probability for cube landing with even number in second time.
[tex]\begin{gathered} P(B)=\frac{3}{6} \\ =\frac{1}{2} \end{gathered}[/tex]Since both rolling of dices are independent to each other. So probability for getting even number on both time is,
[tex]\begin{gathered} P(AandB)=P(A)\cdot P(B) \\ =\frac{1}{2}\cdot\frac{1}{2} \\ =\frac{1}{4} \end{gathered}[/tex]Answer: 1/4
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