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If an object is dropped, the distance it fails during t seconds is given by d(t)=1/2gt^2, where g is about 32ft/sec^2. Find the distance an object would fall in 8 seconds.

If An Object Is Dropped The Distance It Fails During T Seconds Is Given By Dt12gt2 Where G Is About 32ftsec2 Find The Distance An Object Would Fall In 8 Seconds class=

Sagot :

Since the distanc function is given by

[tex]d(t)=\frac{1}{2}gt^2[/tex]

in order to find the distance at 8 seconds, we need to substitute t=8 into this function, that is,

[tex]d(8)=\frac{1}{2}g(8)^2[/tex]

By taking into account that g=32 ft/sec^2, we have

[tex]d(8)=\frac{1}{2}(32)(64)[/tex]

which gives

[tex]\begin{gathered} d(8)=16\times64 \\ d(8)=1024 \end{gathered}[/tex]

Therefore, the answer is 1024 ft, which corresponds to the last option.

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