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11. 9 Reason Abstractly Explain why astudent who runs 3/4 mile in 6 minutes isfaster than a student who runs 1/2 mile in5 minutes.

Sagot :

hello

to solve this question, need to calculate their speeds and compare

student A ran 3/4 miles in 6 mins

[tex]\text{speed}=\frac{dis\tan ce}{time}[/tex]

now we can substitute the values into the equatio

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