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Given z equals quantity 4 plus 7 times I end quantity over quantity 2 minus 6 times I end quantity comma what is z in standard form?

Given Z Equals Quantity 4 Plus 7 Times I End Quantity Over Quantity 2 Minus 6 Times I End Quantity Comma What Is Z In Standard Form class=

Sagot :

ANSWER

[tex]\begin{gathered} z\text{ = -}\frac{17}{20}\text{ + }\frac{19}{20}i \\ \text{option D} \end{gathered}[/tex]

STEP-BY-STEP EXPLANATION:

Given information

[tex]z\text{ = }\frac{4\text{ + 7i}}{2\text{ - 6i}}[/tex]

Step 1: We need to find the conjugate of the denominator

[tex]\begin{gathered} \text{The conjugate of 2 - 6i is 2 + 6i} \\ \text{Conjugate = 2 + 6i} \end{gathered}[/tex]

Step 2: Multiply the conjugate by the numerator and the denominator

[tex]\frac{4\text{ + 7i}}{2\text{ - 6i}}\times\text{ }\frac{2\text{ +6i}}{2\text{ + 6i}}[/tex]

Step 3: Simplify the above expression

[tex]\begin{gathered} z=\frac{(4\times2)\text{ + (4}\times6i)\text{ + (7i }\times2)\text{ + (7i}\times6i)}{(2\times2)\text{ + (2}\times6i)-(6i\times2)-(6i\times6i)} \\ \text{ Expand the parentheses} \\ z=\frac{8+24i+14i+42i^2}{4+12i-12i-36i^2} \\ \text{Recall, }i^2\text{ = -1} \\ \text{Substitute i}^2\text{ = -1 into the expression} \\ z=\frac{8\text{ + 38i + 42(-1)}}{4\text{ - }36(-1)} \\ \\ z=\frac{8\text{ + 38i - 42}}{4\text{ + 36}} \\ \\ z=\frac{8\text{ - 42 + 38i}}{40} \\ z=\frac{-34\text{ + 38i}}{40} \\ z=\text{ }\frac{-34}{40}\text{ + }\frac{38i}{40} \\ z\text{ = -}\frac{17}{20}\text{ + }\frac{19}{20}i \end{gathered}[/tex]