Discover a wealth of knowledge at Westonci.ca, where experts provide answers to your most pressing questions. Join our platform to connect with experts ready to provide precise answers to your questions in different areas. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
To answer this question, first, we have to solve 2x-5=15 for x, and then solve every equation for x.
Solving 2x-5=15 for x, we get:
[tex]\begin{gathered} 2x-5=15, \\ 2x=20, \\ x=10. \end{gathered}[/tex]Now, solving for x:
A)
[tex]\begin{gathered} 2x=10, \\ x=5. \end{gathered}[/tex]B)
[tex]\begin{gathered} 2x=20, \\ x=10. \end{gathered}[/tex]C)
[tex]\begin{gathered} 2(x-5)=15, \\ 2x-10=15, \\ 2x=25, \\ x=\frac{25}{2}\text{.} \end{gathered}[/tex]D)
[tex]\begin{gathered} 2x-20=0, \\ 2x=20, \\ x=10. \end{gathered}[/tex]E)
[tex]\begin{gathered} 4x-10=30, \\ 4x=40, \\ x=10. \end{gathered}[/tex]F)
[tex]\begin{gathered} 15=5-2x, \\ 10=-2x, \\ x=-5. \end{gathered}[/tex]Answer: Options B, D, and E.
Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.
