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a rancher has 80 feet of fencing with which to enclose two adjacent rectangular corrals (see figure). what dimensions should be used so that the enclosed area will be a maximum?

Sagot :

If a rancher has 80 feet of fencing with which to enclose two adjacent rectangular corrals, then for the maximum area the dimensions will be 10 feet and 40/3 feet

From the given figure

4x + 3y = 80 feet

3y = 80 - 4x

y = (80 - 4x) / 3

The area of the rectangle

A = length × width

A = 2x × y

= 2x × (80 - 4x) / 3

Apply distributive property

= (160/3)x - (8/3)x^2

For the maximum area differentiate the values

0 = 160/3 - 16/3x

16/3x = 160/3

x = 160/3 ÷ 16/3

x = 160/3 × 3/16

x = 10 feet

The value of y = (80 - 4x) / 3

y = (80 - 4(10))/3

y = (80-40) / 3

y = 40/3 feet

Therefore, the dimensions are 10 feet and 40/3 feet

Learn more about area here

brainly.com/question/10585228

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