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A spinner is divided into six equal-sized sectors labeled 1 through 6. Dwayne spins this spinner 12 times. Let X

represent the number of 1s that are spun. What are the mean and standard deviation of X?

O Wx = 1, 0x = 1.29

O x = 2,04 = 1.29

OH, = 2,0x = 1.67

O Mx = 10,0x = 2.78

Sagot :

Answer:

b) μ = 2 and σ = 1.29

Step-by-step explanation:

Step(i):-

Given that the A spinner is divided into six equal-sized sectors labelled 1 through 6

Given that the probability of labelled '1'

                      [tex]p = \frac{1}{6}[/tex] =0.16

                     q = 1-p =  1- 0.16 = 0.84

Let 'X' be a random variable in binomial distribution

The mean of the binomial distribution

      μ = n p

     μ  =  [tex]12 (\frac{1}{6} ) = 2[/tex]  

The mean of the binomial distribution  = 2

Step(ii):-

The standard deviation of X

                σ [tex]= \sqrt{npq}[/tex]

               σ = [tex]\sqrt{12(0.16)(0.84}[/tex]

                  σ = [tex]1.269[/tex]

The standard deviation of the binomial distribution

                σ = [tex]1.269[/tex]

Answer:

b

Step-by-step explanation:

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