Answered

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What is an equation of the line that passes through the points (-3, -1) and (6, 2)

Sagot :

Answer:

y = 1/3x

Step-by-step explanation:

Using the slope formula:

[tex]\frac{y2-y1}{x2-x1}[/tex]

Taking (-3,-1) as (x1,y1) and (6,2) as (x2,y2):

(2-(-1))/(6-(-3))

= (2+1)/(6+3)

= 3/9

= 1/3

Hence, the slope (m) is 1/3

Substituting the slope into 'y = mx+c':

y = 1/3x + c

Substituting any point, however, we will be substituting (-3,-1):

-1 = 1/3 * (-3) + c

-1 = -1 + c

c = -1 + 1

= 0

Hence,

y = 1/3x

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