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An elevator is moving upward with a speed of 9.2 m/s. 3.8 seconds later, the elevator is still moving upward, but its speed has increased to 15.8 m/s. What is the average acceleration, in m/s2, of the elevator during the 3.8-s interval? Please round your answer to one decimal place.

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From the calculations, the acceleration of the elevator is obtained as 1.5m/s^2

What is acceleration?

The term acceleration has to do with the rate of change of velocity with time.

Given that;

u =  9.2 m/s

v = 15.8 m/s

t = 3.8

a = ?

The v = u + at

a = v - u/t

a = 15 - 9.2/3.8

a = 1.5m/s^2

Learn more about acceleration:https://brainly.com/question/12550364

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